If you missed the question, and want to try to solve it, go to: “Puzzle: On ‘Jeopardy!’ What’s the Max Anyone Could Win?

To win the max, a player would have to question every answer correctly, and always bet the maximum on the Daily Doubles and in Final Jeopardy. The wrinkle is that each of the Daily Doubles would have to lie behind the minimum dollar-value spaces and be selected last in Single and Double Jeopardy.

Here’s how this jackpot would build:
1. $17,800 for being correct on first 17 posers in Single Jeopardy — that is, all but one $200 space. ($200 + $400 + $600 + $800 + $1,000 = $3,000 x 6 categories = $18,000 – $200 = $17,800.)
2. The Daily Double comes up under the last $200 space, allowing the player to double the $17,800 to $35,600.
3. In Double Jeopardy, which has two Daily Doubles, the first 16 correct questions would net a maximum additional $35,200. ($400 + $800 + $1,200 + $1,600 + $2,000 = $6,000 x 6 = $36,000 – $800 = $35,200.) That brings the total to $70,800.
4. Turn over the first remaining $400 space, wager it all, double the prize to $141,600.
5. Turn over the last $400 space, wager everything, and the total soars to $283,200.
6. Bet it all in Final Jeopardy, and the sum doubles on more glorious time, to $566,400.

Before Uncle Sam’s cut, of course. If my math is right.